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Concordia MATH 203 Readiness Checklist

Check your algebra, functions and trigonometry before MATH 203 with original questions, explained answers and a focused review plan.

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This checklist reviews algebra, functions and trigonometry to prepare for Concordia MATH 203.

Try the six questions without notes. Show your working even when the answer seems obvious. A correct result you cannot explain deserves another look. Use your current course outline to decide what else to review.

1. Simplification and the original domain

Limits often require simplifying an expression near an excluded input. The expression’s domain and its nearby behaviour are different questions. Practise stating the restriction before cancelling.

Worked example

x2−9x−3\frac{x^2-9}{x-3} simplifies to x+3x+3 only when x≠3x\ne3. You can investigate values near 3 without claiming the original expression has a value at 3.

Common mistake. Cancelling terms before factoring, or forgetting the excluded input.

Try it yourself

Simplify x2−4xx\frac{x^2-4x}{x} and state its restriction.

Show answer and reasoning

Factor x(x−4)x(x-4), then cancel xx: the result is x−4x-4, with x≠0x\ne0. The original denominator still excludes zero.

2. Complete quadratic solutions

A graph’s intercepts and an application’s feasible values often start with an equation. Find every solution first, then decide which ones fit the original context.

Worked example

x2−x−6=(x−3)(x+2)x^2-x-6=(x-3)(x+2), so its zeros are 3 and −2-2. Expanding and substituting provide independent checks.

Common mistake. Keeping just the positive root without a reason from the problem.

Try it yourself

Solve x2+2x−8=0x^2+2x-8=0.

Show answer and reasoning

4 and −2-2 multiply to −8-8 and add to 2. Thus (x+4)(x−2)=0(x+4)(x-2)=0 gives x=−4x=-4 or x=2x=2.

3. Algebraic inputs to a function

Let xx be a starting input and let hh be the change in that input; the new input is x+hx+h. For a function gg defined at both inputs, a difference quotient divides the change in output, g(x+h)−g(x)g(x+h)-g(x), by the nonzero input change hh. First practise the substitution: replace every occurrence of the input, preserve parentheses, then simplify. In the example the starting input is 2.

Worked example

For g(x)=x2g(x)=x^2, g(2+h)−g(2)=(2+h)2−4=4h+h2.\begin{aligned}&g(2+h)-g(2)\\&=(2+h)^2-4\\&=4h+h^2\end{aligned}\text{.} Dividing by hh gives 4+h4+h for h≠0h\ne0.

Common mistake. Writing (2+h)2=4+h2(2+h)^2=4+h^2 drops the middle term 4h4h. Expand both factors before collecting terms.

Try it yourself

Let aa be any real number. If f(x)=x2−3xf(x)=x^2-3x, find f(a+1)f(a+1).

Show answer and reasoning

(a+1)2−3(a+1)=a2+2a+1−3a−3=a2−a−2.\begin{aligned}&(a+1)^2-3(a+1)\\&=a^2+2a+1-3a-3\\&=a^2-a-2.\end{aligned}

4. Radians and familiar angles

Review the unit circle, quadrant signs and exact trigonometric values. Radians are especially important for the standard calculus formulas involving sine and cosine. On the circle of radius 1 centred at the origin, cosine is the horizontal coordinate and sine the vertical coordinate. A reference angle is the acute angle between the terminal side and the horizontal axis; use the quadrant to assign the signs.

Worked example

A half-turn is π\pi radians. For example, 120∘×π180∘=2π3120^\circ\times\frac{\pi}{180^\circ}=\frac{2\pi}{3} radians. This angle lies in quadrant II, where sine is positive. Its reference angle is π−2π3=π3\pi-\frac{2\pi}{3}=\frac{\pi}{3}, so sin⁡(2π3)=sin⁡(π3)=32\sin(\frac{2\pi}{3})=\sin(\frac{\pi}{3})=\frac{\sqrt3}{2}.

Common mistake. Using a calculator in degree mode when the input is in radians.

Try it yourself

Convert 150∘150^\circ to radians and find its sine.

Show answer and reasoning

150π180=5π6.\frac{150\pi}{180}=\frac{5\pi}{6}\text{.} The angle is in quadrant II with reference angle π6\frac{\pi}{6}, so sin⁡ ⁣(5π6)=12\sin\!\left(\frac{5\pi}{6}\right)=\frac{1}{2}.

5. Logarithms as inverse operations

Exponential and logarithmic functions appear throughout calculus. First make the exponential the subject of an equation, then apply its inverse. Keep exact values when possible. The natural logarithm ln⁡\ln has base e≈2.718e\approx2.718, so ln⁡(ex)=x\ln(e^x)=x. Its real argument must be positive.

Worked example

e2x=5e^{2x}=5 gives 2x=ln⁡52x=\ln 5 and x=ln⁡52x=\frac{\ln 5}{2}. A logarithm is an inverse function, not division by its base.

Common mistake. For positive numbers aa and bb, do not split ln⁡(a+b)\ln(a+b) into ln⁡a+ln⁡b\ln a+\ln b. The familiar sum of logarithms comes from a product, not a sum inside the logarithm.

Try it yourself

Solve 3ex=123e^x=12.

Show answer and reasoning

Divide by 3 to obtain ex=4e^x=4. Apply ln⁡\ln to both sides: x=ln⁡4x=\ln 4.

6. Average rate versus average output

A rate measures change in output per unit change in input. A derivative refines this idea locally, so interpret the quotient as well as calculating it. Subtract the initial output from the final output, then divide by final input minus initial input. The two inputs must differ.

Worked example

Suppose an object’s position is s(t)=t2s(t)=t^2 metres, with tt measured in seconds. Between t=1t=1 and t=3t=3, its positions are 1 m and 9 m. Its average velocity is s(3)−s(1)3−1=9−12=4\frac{s(3)-s(1)}{3-1}=\frac{9-1}{2}=4 m/s. By contrast, 1+92=5\frac{1+9}{2}=5 m is the average of the two endpoint positions; it is a position, not a rate.

Common mistake. Using s(3)+s(1)2\frac{s(3)+s(1)}{2} gives the average of the two endpoint positions, not their average rate of change.

Try it yourself

Let tt be a real input and p(t)=t2+1p(t)=t^2+1 its output. Find the average rate from t=2t=2 to t=5t=5.

Show answer and reasoning

p(5)−p(2)5−2=26−53=7.\begin{aligned}\frac{p(5)-p(2)}{5-2}&=\frac{26-5}{3}\\&=7\end{aligned}\text{.} We compare output differences, not the average of 26 and 5.

Your next revision session

  • Mark a topic comfortable only if you can explain every step without a hint.
  • Choose two uncertain topics. Study one worked example, solve three new variations, and retry a day later without notes.
  • For MATH 203 exam preparation, add derivative-rule selection, curve interpretation and application setup according to your section’s current outline. This checklist alone is not a complete course review.

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