Centennial College · MT-121

Centennial MT-121 tutoring

Help with forces, moments, support reactions and friction in Centennial MT-121.

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Course overview

MT-121 studies bodies in equilibrium using applied mechanics. Centennial’s current curriculum includes this course in Mechanical Engineering Technician – Design and Mechanical Engineering Technology - Design and Industrial (Optional Co-op). The published scope covers vectors, forces, moments, couples, resultants, centroids, moments of inertia, free-body diagrams and friction. The central habit is to translate a physical support or contact into the forces it can exert.

MT-121 topics to review

Vectors, force resultants and free-body diagramsMoments, couples and equilibrium equationsCentroids and moments of inertiaFriction and contact-force assumptions

Common difficulties

  • Balancing forces but forgetting rotational equilibrium
  • Using the full distance instead of the perpendicular moment arm

Preparing for this course

Review right-triangle trigonometry, simultaneous equations and units. For a moment, mark the perpendicular distance from the chosen point to the force’s line of action. Keep a consistent clockwise or counterclockwise sign convention, and identify which reaction components each idealized support permits.

Registration requirements

The guidance above is study preparation, not an eligibility decision. Confirm current prerequisites, restrictions and availability with Centennial College.

Check the official course catalogue

Balance a beam with an off-centre load

A uniform 4 m4\text{ m} horizontal beam weighs 200 N200\text{ N}. A pin supports its left end A and a roller on a horizontal surface supports its right end B. A downward 600 N600\text{ N} load acts 1 m1\text{ m} from A. Find the support reactions.

Show the reasoning
  1. Isolate the beam

    Let AxA_x and AyA_y be the horizontal and vertical reaction components at A, and ByB_y the vertical reaction at B. Draw them positive to the right and upward. Place the beam’s weight at its midpoint, 2 m2\text{ m} from A. The pin supplies no reaction couple; the roller rests on a horizontal surface.

  2. Take moments about A

    Choose counterclockwise as positive. The reactions at A have zero moment about A, so 4By−600(1)−200(2)=04B_y-600(1)-200(2)=0. Therefore By=250 NB_y=250\text{ N} upward. Every term in the moment equation has units of newton-metres.

  3. Finish the force balances

    Vertical equilibrium gives Ay+250−600−200=0A_y+250-600-200=0, hence Ay=550 NA_y=550\text{ N} upward. Horizontal equilibrium gives Ax=0A_x=0. The reactions total 800 N800\text{ N}, and the larger reaction is nearer the concentrated load.

Try a changed problem

Repeat for a uniform 6 m6\text{ m} beam weighing 300 N300\text{ N}, with a 900 N900\text{ N} downward load 4 m4\text{ m} from A and the same support types.

Check your reasoning

From 6By=900(4)+300(3)6B_y=900(4)+300(3), obtain By=750 NB_y=750\text{ N}. Then Ay=1200−750=450 NA_y=1200-750=450\text{ N} and Ax=0A_x=0. The load is now nearer B, which carries the larger reaction.

How tutoring can help

Start with a support-reaction or friction question you’re stuck on, or a concept you’d like to understand better. A tutor can help you isolate the body, draw its forces and choose a point for the moment equation. We can solve it together, then move a load and explore how the reactions change.

Exam preparation for MT-121

Practise writing all independent equilibrium equations, even when one immediately gives zero. Finish by substituting reactions into an unused or rearranged balance. For friction questions, distinguish an actual friction force from its maximum possible static value.

Use your section’s outline to choose the chapters to review. We work through permitted practice and comparable problems, without completing graded assignments or exams on your behalf.

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MT-121 · official course reference