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La Cité · 027583 TEC

La Cité 027583 TEC tutoring

Help with position, velocity, acceleration and dynamics in 027583 TEC.

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Online 60 min: $55 CAD · PricingMidterm & final exam helpSeparate tangential and radial accelerationFree study guide for 027583 TEC
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Course overview

027583 TEC examines the motion and dynamics of solid bodies in La Cité’s mechanical-engineering technology program. Kinematics describes position, velocity and acceleration; dynamics relates motion to its causes. In rotational motion, a point can accelerate even when angular speed is constant, because its velocity changes direction.

027583 TEC topics to review

Kinematics of solid bodiesVelocity and acceleration relationshipsDynamics of mechanical motion

Common difficulties

  • Confusing angular acceleration with the full acceleration of a point
  • Adding perpendicular acceleration magnitudes as scalars

Preparing for this course

Review radians, unit conversions and perpendicular vector components. Distinguish angular quantities from the linear motion of a point on a rotating body. The radius matters when converting angular speed to linear speed.

Registration requirements

The guidance above is study preparation, not an eligibility decision. Confirm current prerequisites, restrictions and availability with La Cité.

Check the official course catalogue

Separate tangential and radial acceleration

A disk rotates about a fixed axis through its stationary centre and starts from rest with constant angular acceleration α=4 rad/s2\alpha=4\text{ rad/s}^2. For a point 0.25 m from the centre, find angular speed, tangential speed and both acceleration components after 3 s.

Show the reasoning

  1. Find the angular speed first

    Let rr be the point’s distance from the axis, tt elapsed time and ω0\omega_0 the initial angular speed. With constant angular acceleration, ω=ω0+αt=0+4(3)=12 rad/s\omega=\omega_0+\alpha t=0+4(3)=12\text{ rad/s}. Linear speed is v=rω=0.25(12)=3 m/sv=r\omega=0.25(12)=3\text{ m/s}.

  2. Separate changing speed from changing direction

    Tangential acceleration is at=rα=1 m/s2a_t=r\alpha=1\text{ m/s}^2. Radial acceleration points toward the centre and has magnitude ar=rω2=0.25(144)=36 m/s2a_r=r\omega^2=0.25(144)=36\text{ m/s}^2.

  3. Combine only as vectors

    The components are perpendicular. If the total magnitude is needed, it is 12+362=1297 m/s2\sqrt{1^2+36^2}=\sqrt{1297}\text{ m/s}^2, not 37. A constant α\alpha does not make ara_r constant because ω\omega changes.

Try a changed problem

At the same time, consider a point 0.50 m from the centre. Which quantities double?

Check your reasoning

Angular speed remains 12 rad/s. The linear speed becomes 6 m/s, tangential acceleration 2 m/s² and radial acceleration 72 m/s². Each linear quantity here is proportional to radius.

How tutoring can help

A tutor can help you picture the motion before choosing equations. For a rotating object, you can mark a point together and explain the difference between a change in speed and a change in direction. The tutor can then guide you through the angular and linear quantities, units and calculation, starting wherever you need help.

Exam preparation for 027583 TEC

Build a short list of what each symbol measures before solving a motion problem. Practise checking a result with dimensions and with a limiting case such as zero angular acceleration. Follow the current chapter for the required rigid-body models.

Use your section’s outline to choose the chapters to review. We work through permitted practice and comparable problems, without completing graded assignments or exams on your behalf.

Independent practice

Free practice and study guides for 027583 TEC

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027583 TEC · official course reference